Updating a datagridview dating croatian women
Configuration; namespace GRP_02_03_SACP So, in that Method That Return List() you can build a List (List is a class) with all the items you need.The Data Grid View control supports the standard Windows Forms data binding model, so it can bind to a variety of data sources. Fill(table); Binding Source b Source = new Binding Source(); b Source. They have to do with redrawing the control which is why new rows don't appear. Select Command = new My Sql Command(sql Select All, con); Data Table table = new Data Table(); My DA. Close(); are methods that are inherited from Control.
Data graye: Your solution is closer to what I'm looking for and you will get most of the points.
Open(); My Sql Data Adapter My DA = new My Sql Data Adapter(); string sql Select All = "SELECT * from dailyprice"; My DA.
After entering data into all the textbox, and after clicking the submit button, it won't immediately show in the datagridview, I need to reopen the form in order to see the new inserted row.
Just answer this: I plan to run in disconnected mode but will update the database row by row.
When user leaves a row, I plan to update and disconnect What is an easy way of detecting a key change?
However, that's not really "in the spirit" of the disconnected model... Your way is more, Fill, Update, Update, Update, etc...